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Thread: Brick stacker - GIF

  1. #1
    Supporting Member Altair's Avatar
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    Brick stacker - GIF


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  2. The Following 5 Users Say Thank You to Altair For This Useful Post:

    johncg (Jun 23, 2023), nova_robotics (Jun 24, 2023), Philip Davies (Jun 24, 2023), Scotty1 (Jun 23, 2023), Toolmaker51 (Jun 22, 2023)

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    Supporting Member Toolmaker51's Avatar
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    Sometime, might attempt calculating quantity of brick in my structure, built 1896. The pattern is hard to visualize per cubic means, a foot thick.

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  4. #3
    Supporting Member bob_3000's Avatar
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    Quote Originally Posted by Toolmaker51 View Post
    Sometime, might attempt calculating quantity of brick in my structure, built 1896. The pattern is hard to visualize per cubic means, a foot thick.
    My place was built in 1876, balloon frame construction, it looks a foot thick...but it aint.

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    Supporting Member Toolmaker51's Avatar
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    No framing beside insignificant door jambs. The original roof (barely 2:12), supported by 15 6x6 nominal posts, the set-in rafters were retained in pockets formed by brick too.
    Now, trussed roof sits on 2x12 plates bonded & anchored atop walls. One wall was a pediment for drainage on a zero lot line. That was lowered a few courses to lowest plane, still have 15'8" as before, but now free span.
    Win. Win.
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    bob_3000 (Jun 24, 2023)

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    Supporting Member Philip Davies's Avatar
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    On the subject of counting bricks, two evenings ago I was sent a picture of a crinkle crankle wall, which is laid to a sinusoidal foundation, a single brick thickness, which is a saving on brickwork, because of the strength in the pattern, and these have been made since the 17th century at least. So I wondered how the brickie laid it out and calculated how many bricks he would need (assuming he couldn’t do calculus) .
    A load of bricks was calculated at 500 per load, but I seem to remember there were other quantities, but can’t find a reference to any other in my old mensuration tables.
    I worked out a method to set out and to calculate, but wonder if there is an optimum sinusoidal curve which gives maximum strength. I learned calculus at school, but have never needed it, until now, but I would like to know how many bricks would be saved!

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    Supporting Member mklotz's Avatar
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    The first step in calculating any savings afforded by the sinuous design would be to calculate the length of a given section of a sinuous wall. Referring to Example 8.1.2 here...

    https://math.libretexts.org/Bookshel...%3A_Arc_Length

    says that the length of a sine curve between zero and pi (radians) is 3.8202 versus the straight line length of 3.14.

    Given that the serpentine wall is longer than a straight wall spanning the same distance, calculating savings in material, if any, will depend on the assumptions made about how the linear wall is formed (e.g. two brick width vs one on serpentine), buttressed, or otherwise strengthened.
    ---
    Regards, Marv

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    Supporting Member Toolmaker51's Avatar
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    Phillip, no contest for Marv's contribution, but a brickload of info here. Many sites I looked at for my question appeared in this too...

    https://www.google.com/search?client...for+brick+work



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