I am not Marv but this is pretty elementary. The falling would have taken the same time as the time rising so if we say 2 secs to fall, the distance is 1/2 x a x t^2.
a = 9.807 so the altitude = 1/2 x 9.807 x 2^2 = 19.6 say 20 m. This ignores aerodynamic drag so if that is taken into account the height would be less.
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