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# Thread: Hyperboloid of revolution

2. ## The Following 10 Users Say Thank You to mklotz For This Useful Post:

baja (May 19, 2019), bruce.desertrat (May 23, 2019), high-side (May 14, 2019), Jon (May 11, 2019), JTG (May 14, 2019), Marnat3 (May 18, 2019), rgsparber (May 18, 2019), Scotsman Hosie (May 14, 2019), Seedtick (May 13, 2019), Slim-123 (May 13, 2019)

3. The Cartesian equation of a hyperboloid is:

(x^2 + y^2)/a^2 - z^2/b^2 = 1

With the origin set at the center of the figure, define the x direction to be left/right and the z direction up/down. The y direction is then perpendicular to the board. To obtain the equation of the cuts in the board, take y to be zero, i.e., the equation in the plane of the board.

What results is the Cartesian equation of an hyperbola.

x^2/a^2 - z^2/b^2 = 1

When z = 0 , corresponding to a horizontal line through the center of the board, we have x = a, which determines the separation of the two curved lines forming the hyperpola.

For z nonzero, we have:

x^2 = a^2 * (1 + z^2/b^2)

so, as z increases the separation between the +x value and the -x value becomes greater and greater thus creating the characteristic flare of the hyperbola.

4. ## The Following 2 Users Say Thank You to Jon For This Useful Post:

baja (Jun 16, 2019), Seedtick (Jun 12, 2019)

5. Originally Posted by Jon
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When I next hear someone speaking in Hyperboles this will be the vision in my mind.

6. Watching a college majorette doing her routine on stage in a cloud of vapor under ultraviolet light while she spins up holding her baton at a certain angle makes a lasting impression of a 3 dimensional hyperbola being created in the vapor

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